find the measure of an angle which is 36 degrees more than its complement
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here let the unknown angle be 'x' and the complement angle be x+36
A/Q
x+(x+36)=90 degree (as sum of two complementary angles is 90 degree)
2x+36=90
2x=90-36
2x=54
x=54/2
x=27
the angle is
x+36=27+36=64
A/Q
x+(x+36)=90 degree (as sum of two complementary angles is 90 degree)
2x+36=90
2x=90-36
2x=54
x=54/2
x=27
the angle is
x+36=27+36=64
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