Find the measure of an which is 36 degree more than four- fifth of its supplement
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The angle is 60 degree by solution
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how will it be?????!
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let then. be=x
supplement of x =180°-x
required=(4/5 of 180°-x)+36°
=(4of36°-x)+36°
=144°-x+36°
=-x+36°+144°
=-x+180°ans.
supplement of x =180°-x
required=(4/5 of 180°-x)+36°
=(4of36°-x)+36°
=144°-x+36°
=-x+36°+144°
=-x+180°ans.
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