find the measure of angle apb
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angle APB is 105 degree as
its a palleogram and opposite angles of parallelogram r equal so angle A =100 and angleB=50 and it is said that the bisector of these angles meet at p so angle PAB=50 and angle PBA =25 no apply angle sum property of triangle
a+b+c=180
50+25+p=180
75+p=180
p=180-75
p=105
its a palleogram and opposite angles of parallelogram r equal so angle A =100 and angleB=50 and it is said that the bisector of these angles meet at p so angle PAB=50 and angle PBA =25 no apply angle sum property of triangle
a+b+c=180
50+25+p=180
75+p=180
p=180-75
p=105
Muddassir11:
ya
sorry i didnt paid attention to it
can i correct my answer
so I think the answer should be 75
how
As it is a quad. the total sum of it's angles is 360.When we subtract the sum of angle D and C the sum of angle A and be remains 210 as AP and BP are the bisectors of angle A and angle B respectively so the sum of angle PAB and angle PBA will be 105
ABP is a triangle so the sum of angles is 180
when we subtract 105 from 180 we get 75
Am I correct?
Yeah thanks
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