Question

find the measure of angle BOC and angle AOC


plzz please answer this question please ​

Answer 1

4x-3y=20 ---------------(1)

AOC+BOC = 180(linear pair)

3y-10+2x=180

3y+2x=190---------------(2)

(2+1)

4x-3y=20

2x+3y=190

6x=210

x=35

from (1)

140-3y=20

3y=120

y=40

AOC=120-10=110

BOC=70

I hope this helps you

Answer 2

SolutioN :

★ Diagram.

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\put(0,0){\line(1,0){30}}\put(14,0){\line(7,3){7}}\put(13,-3){ O }\put(16,17){ C }\put(4,1){ 3y-1 }\put(17,1){ 2x }\put(-3,0){ A }\put(31,0){ B }\end{picture}$

$\rule{200}2$

• AB is a line and OC ray stand on line AB.
• ∠AOC = 3y - 1. and ∠BOC = 2x.

So,

• AB is line ( given ) We know that and line always straight with 180°

$\tt : \implies \angle AOC + \angle COB =180\degree.$

$\tt : \implies 3y-1+2x=180\degree.$

$\tt : \implies 2x + 3y=181\degree. - - - (1)$

And,

$\tt : \implies 4x - 3y = 20\degree. - - - (2)$

Now, By Using Elimination Methods.

$\tt : \implies 6x = 201.$

$\tt : \implies x = \dfrac{201}{6}$

$\tt : \implies x = 33.5$

★ Now, Putting the value of x in Equation ( 1 ) We get.

$\tt : \implies 2x + 3y = 181.$

$\tt : \implies 2(33.5) + 3y = 181.$

$\tt : \implies 67 + 3y = 181.$

$\tt : \implies 3y = 181 - 67.$

$\tt : \implies 3y = 114.$

$\tt : \implies y = 38.$

★ Now, Let's Find the ∠AOC = 3y - 1. and ∠BOC = 2x.

$\tt : \implies \angle AOC = 3y - 1.$

$\tt : \implies \angle AOC = 3(38)- 1.$

$\tt : \implies \angle AOC = 114 - 1.$

$\tt : \implies \angle AOC = 113.$

And,

$\tt : \implies \angle BOC = 2x.$

$\tt : \implies \angle BOC = 2(33.5)$

$\tt : \implies \angle BOC = 67 \degree.$