find the measure of angle BPC.
I want the whole sum... can anybody help it out plz..I want it asap...
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Answer: <BAP=<PDC=40
IN TRIANGLE PCD, <PCD+<CDP+<CPD=180,
<CPD=180-(55+40)=180-95=85
<CPD+<CPB=180 (LINEAR PAIR)
<CPB=180-85=95. OR <BPC=95
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