Math, asked by arunkumar3978, 1 year ago

find the measure of angle in
ABC (in degree)in the parallelogram.
ABCD As shown in
the figure

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Answers

Answered by omane995
1

answer =68 degree

Step-by-step explanation:

9x +5 + 16x =180

25x +5 =180

25x=180-5

25x=175

x=175/25

x=7

9x+5=9 X 7 +5

=63 +5

=68

16x =16 X 7

=112

angle ABC +angle BCD=180. (interior.

angles)

ABC+16x =180

ABC+112=180 (BCD=16x=112)

ABC=180-112

ABC=68

Answered by DarkPsycho
0

Answer:

68°

Step-by-step explanation:

angle ABC= 9x+5 [alternate interior angles]

angle ABC + angle DBC = 180° [sum of co interior angles]

9x+5+16x=180

25x+5=180

25x=175

x=175/25

x= 7

therefore, angle ABC = (9*7) +5

63+5

68°

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