Question

Find the measure of angle of a parallelogram if one angle is 20 degree less than twice the smallest angle

Answer 1

Let the the smallest angle be x 
than the other angle = 2x - 20
as we know in parallelogram the angle opposite sides are equal we can say that the angles of the parallelogram are=
x,2 x-20,x ,2 x-20
the sum of all the angles are 360 in a parallelogram
so, x+2 x-20+x+2 x-20=360
6x -20 = 360
6x=360+40
6 x = 400
x =400/6
x = 66 2/3 (when we simplify 4/6)
2 x -20 = (66 2/3 ×2) - 20
2x - 20 = 113 1/3
∴ the angles are 66 2/3 ,113 1/3 , 66 2/3 ,113 1/3 ( ans)

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