Question

find the measure of angle of a parallelogram if one angle is 20° less than twice the smallest angle

Answer 1

let the angle be x
other angle will be 2x-20
sum x+2x-20=180
3x=200
x=200/3

Answer 2

Let the smallest angle = x

Now, the biggest angle = 2x-20° .

Then ,

As we know :

x+2x-20° = 180° [Property of parallelogram]

3x=180°+20°

3x = 200°

x = 200/3°

Now,

The biggest angle =

2x-20°

=
$2 \times \frac{200}{3} - 20 \\ \frac{400}{3} - 20 \\ \frac{400 - 120}{3} \\ \frac{280}{3}$


#Be Brainly !!