find the measure of angle of elevation of top of a tower 75 root 3m high from a point of distance 75m from foot of tower in a horizontal plane
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Answer
Let the angle of deviation be θ.
In △ACB,
⇒tanθ=
BC
AB
=
75
75
3
⇒tanθ=
3
⇒θ=60
∘
Hence, the answer is 60
∘
.
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