Math, asked by copycat82, 27 days ago

find the measure of angle theta when theta is acute



no spamming or I WILL report it​

Attachments:

Answers

Answered by vyshunarayanan
1

2 { \cos }^{2} 5x =  1

 { \cos }^{2} 5x =  \frac{1}{2}

 \cos(5x)  =  \frac{1}{ \sqrt{2} }

 \cos(5x)  =  \cos(45)

5x = 45

x = 9

this is because cos 45=1/√2

Similar questions