Find the measure of angle which is 36degree more than its complement
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Answered by
4
let the angle be x
then its complement = 90°-x
according to question ,
x-(90-x) = 36
x-90+x = 36
2x = 36+90 => 126°
x = 126°/2 => 63°
hope this helps
then its complement = 90°-x
according to question ,
x-(90-x) = 36
x-90+x = 36
2x = 36+90 => 126°
x = 126°/2 => 63°
hope this helps
Answered by
4
Hey there!
Let the angle be x
Then, its complement = 90-x
A/q,
(90-x) + 36 = x
⇒ 126 = x+x
⇒ x = 126/2
∴ x = 63
----------------------------------------------------------------------------------------------------
Hope it is helpful
Let the angle be x
Then, its complement = 90-x
A/q,
(90-x) + 36 = x
⇒ 126 = x+x
⇒ x = 126/2
∴ x = 63
----------------------------------------------------------------------------------------------------
Hope it is helpful
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