find the measure of angles A B C D in the following figure
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★ Solution :
We know that, sum of all angles of a quadrilateral = 360°.
so,
100 + 40 + 120 + c = 360°
260 + c = 360
c = 360 - 260
→ c = 100°
40° and a are linear pairs
40 + a = 180
a = 180-40
→ a = 140°
c and d are linear pairs
c+d = 180
100 + d = 180
d = 180 - 100
→ d = 80°
100° and b are linear pairs
100 + b = 180
b = 180 - 100
→ b = 80°
Answered by
2
Answer:
angle A=140°
angle B=80°
angle C=100°
angle D=80°
Step-by-step explanation:
PQRS= 360°
40+100+120+c = 360
260+c=360
c=360-260
c=100°
angle p+a=180(stright angle)
40+a=180
a=180-40
a=140°
angle s+b=180(stright angle)
100+b=180
b=180-100
b=80°
angle c+d=180(stright angle)
100+d=180
d=180-100
d=80°
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