Math, asked by geetaagrahari0708, 1 day ago

find the measure of angles marked ‘?' in each of the following
question number 5 b​

Attachments:

Answers

Answered by talpadadilip417
7

Step-by-step explanation:

Answer 5(b):-

\[ \begin{array}{l} \rm \angle C A B+\angle A C B+\angle C B A=180^{\circ} \\ \\   \rm\Rightarrow 2 x+4 x+3 x=180^{\circ} \\ \\  \rm \Rightarrow x=\dfrac{180^{\circ}}{9}=20^{\circ} \\  \\  \rm\angle D A C+\angle C A B=180^{\circ} \\  \\  \rm\Rightarrow \angle D A C+2 x=180^{\circ} \\ \\  \rm \Rightarrow \angle D A C=180^{\circ}-40^{\circ}=140^{\circ} \\  \\  \boxed{\color{green}  \rm\Rightarrow \angle D A C=140 \degree} \end{array} \]

Hence the answer is 140°.

Answered by Talpadadilip783
1

   \scriptsize\colorbox{lightyellow} {\text{ \bf♕ Brainliest answer }}

 \rule{300pt}{0.1pt}

Answer 5(b):-

\begin{gathered} \begin{array}{l} \rm \angle C A B+\angle A C B+\angle C B A=180^{\circ} \\ \\ \rm\Rightarrow 2 x+4 x+3 x=180^{\circ} \\ \\ \rm \Rightarrow x=\dfrac{180^{\circ}}{9}=20^{\circ} \\ \\ \rm\angle D A C+\angle C A B=180^{\circ} \\ \\ \rm\Rightarrow \angle D A C+2 x=180^{\circ} \\ \\ \rm \Rightarrow \angle D A C=180^{\circ}-40^{\circ}=140^{\circ} \\ \\ \boxed{\color{green} \rm\Rightarrow \angle D A C=140 \degree} \end{array} \end{gathered}

Hence the answer is 140°.

Similar questions