Find the measure of each angle of a parallelogram, if larger angle is 30c less than twice
the smaller angle.
Answers
Answered by
64
Hi ,
In a parallelogram sum of the adjacent angles
equals supplementary.
opposite angles are equal.
Let the smaller angle = x°
larger angle = twice the smaller angle - 30°
=2x° - 30°
x° +2 x° - 30 = 180°
3x° = 180 + 30
3x = 210
x = 210 / 3
x = 70°
Therefore,
smaller angle = x = 70°
larger angle = 2x - 30
= 2 × 70 - 30
= 140 - 30
= 110°
Required parallelogram angles are 70° , 110° ,
70° , 110°
I hope this helps you.
:)
In a parallelogram sum of the adjacent angles
equals supplementary.
opposite angles are equal.
Let the smaller angle = x°
larger angle = twice the smaller angle - 30°
=2x° - 30°
x° +2 x° - 30 = 180°
3x° = 180 + 30
3x = 210
x = 210 / 3
x = 70°
Therefore,
smaller angle = x = 70°
larger angle = 2x - 30
= 2 × 70 - 30
= 140 - 30
= 110°
Required parallelogram angles are 70° , 110° ,
70° , 110°
I hope this helps you.
:)
Answered by
13
Answer:
x+2×-30=180
3x=210
x=70
2x-30,x=70 just prroved
2×70-30
110 hope it helpful to u
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