Question

find the measure of each angle of a parallelogram if larger angle is 30° less than twicr the smaller angles

Answer 1

the sum of the smaller angles = 2x
the sum of the larger angles = 2(2x+30)
sum of 4 angles = 360
(x) + (x) + (2x+30) + (2x+30) = 360
6x + 60 = 360
6x = 360 - 60
6x = 300
x = 300/6
x = 50
the four angles are
x , x, 2x+30, 2x + 30
= 50, 50, 2(50)+30,2(50)+30
= 50,50,130,130