Question

Find the measure of each angle of a
parallelogram, if one of its
angle is 30degrees less than twice the smallest angle​

Answer 1

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Answer:

Let the smallest angle

Second angle 2x-30

Sum of two adjacent angles in a parallelogram 3D 180

x+2x-30=180

3x=180+30

3x=210

x=210/3

x=70

Second angle = 2x-30=2* 7030110

Therefore

Four angles of the parallelogram are

Four angles of the parallelogram are70,110,70,110