Question

find the measure of each angle of a parallelogram if one of its angle is 30 less than twice the smallest angle ​

Answer 1

Answer:

Let the smallest angle be x

One angle = 2x - 30°

∴ x + 2x - 30° = 180°

⇒ 3x = 210°

⇒ x = 70°

∴ 2x - 30° = 110°

∴ Angles are 70°, 110° , 70°, 110° .

Step-by-step explanation:

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