Math, asked by mehulmayan290308, 1 month ago

find the measure of each angle of a parallelogram if one of its angle is 30 less than twice the smallest angle ​

Answers

Answered by son36
4

Step-by-step explanation:

Let x and 2x-30° bet the two angles in a parallelogram.

x+2x-30°=180°

3x=180°+30°

3x=210°

x=70°

Other angle = 180°-70° =110°

Answered by random1415
0

Answer:

70°,110°,70°,110°

Step-by-step explanation:

x+2x-30=180 (adjacent angles are equal)

3x=210

x=70°

larger angle= 110°

according to the attached diagram,

angle A=angle C=70° (opposite angles are equal)

angle B=angle D=110° (opposite angles)

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