Find the measure of each angle of a parallelogram, if one of its angles is
30° less than twice the smallest angles
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Answer:
110, 70 , 110 , 70
Step-by-step explanation:
Sum of angles of parallelogram is 360
⇒x+(2x−30)+x+(2x−30)=360
x +(2x−30) +x +(2x−30) =360
6x =420
⇒x =70
(2x−30) =2×70−30
=110
Therefore the angles are 110, 70, 110, 70
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