Find the measure of each angle of a parallelogram, if one of its angle is 60° less than twice the smallest angle.
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Answer:
80°, 100°, 80°, 100°
Step-by-step explanation:
let the smallest angle be x
one of the angle is 2x-60
other two angles are x, 2x-60
sum of all angles in quadrilateral is 360°
x+2x-60+x+2x-60=360
6x-120=360
6x=480
x=80°
the angles are 80°, 2(80)-60=100°,80°, 100°
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