Question

Find the measure of each angle of a parallelogram if the larger angle is 30 degree less than twice the smaller angle.​

Answer 1

Answer:

Step-by-step explanation:

et the smaller angle be x  

so, other angle is 2x-30  

by angle prop. of parallelogram measures of angles are x, x, 2x-30, 2x-30  

by angle sum property  

x+x+2x-30+2x-30=360  

6x-60=360  

6x=420  

x=70  

so, angles are  

70  

110  

70  

110

Prajwal · 9 years ago

0 Thumbs up 0 Thumbs down Report Abuse Comment

bagsprosh

There are four angles within a Parallelogram.  

All 4 together add up to 360 Degrees.  

And there are 2 angles each of the same value  

Let "a" and "b" be the angles  

So 2a + 2b = 360 (Equation1)  

And a - 2b = 30 (Equation 2)  

Add both equaions and you get  

3a = 390  

So a = 130 Degrees  

b = 50 Degrees (the smaller angle)

bagsprosh · 9 years ago

0 Thumbs up 0 Thumbs down Report Abuse Comment

Kuleena

let one of its angles be x  

therefore the other angle is 2x-30  

In a parallelogram, opposite angles are equal.  

So, all the angles are x,x,2x-30,2x-30.  

sum of the angles of a parallelogram=360*  

by the given condition,  

x+x+2x-30+2x-30 = 360  

2x+2x-30+2x-30 = 360  

6x -60 = 360  

6x = 420  

x = 70  

therefore smallest angle = 70*  

other angle =70*2-30 = 110*  

all the angles of a parallelogram are 70*,70*,110*,110*