Question

Find the measure of each angle of a triangle when two
angles are equal and the third angle is greater than each of these
angles by 30°.​

Answer 1

Answer:

1st=50

2nd=50

3rd=80

Step-by-step explanation:

Let the 1st and 2nd angle be=x

then 3rd angle=x+30

as we know sum of all angles of triangle=180

x+x+x+30=180

3x=150

x=150/3=50

1 st and 2nd =50,50

3rd angle=80

Answer 2

Answer:

Let the two equal angles be x

the third angle will be x+30

 therefore

2x+x+30 = 180   (ASP)

x=50

So, two equal angles of the triangle are 50° and the third angle is 80°.