Question

find the measure of each exterior angle and each interior angle of regular pentagon

Answer 1

It depends on the no. Of sides of a regular polygon.
Each exterior angle will be 360°/n.
And, interior angle will be sum of angle of that polygon divided by no. Of sides i.e. (n-2)*180° /n
and, Here it is a pentagon i.e. n = 5. So, exterior angles will be 360/5 = 72°.
Interior angles will be
(5-2)180°/5 = 3*36 = 108°.

Answer 2

Each interior angles =2n-4 mutiply90 upon 'n' (n=no. Of side )
Each exterior angle =360 upon 'n'