Find the measure of each exterior angle of a regular polygon of 10sides
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Answered by
3
Sum of interior angle of n side equiangular polygon
= (n-2)x 180
Therefore each interior angle = (n-2)180/n
Similarly exterior angle = 360/n = 36 deg
= (n-2)x 180
Therefore each interior angle = (n-2)180/n
Similarly exterior angle = 360/n = 36 deg
Answered by
9
Each exterior angle of a polygon=10degree
Let no of sides =x
x=360/n
10=360/n
n=360/10
n=36degree answer.
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Let no of sides =x
x=360/n
10=360/n
n=360/10
n=36degree answer.
Hope it helps you...
plz mark me as brainilest....
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