Question

find the measure of each interior and exterior angles of a regular pentagon

Answer 1

interior angle of Pentagon=(2n-4)*90degree
=(2*5-4)*90degree
=(10-4)*90 degree
=6*90degree
=540degree
hence,each interior angle of Pentagon measures 540°.

exterior angle of regular Pentagon=360°/n
=360°/5=72°
hence each exterior angle of regular Pentagon measures 72°.
hope it will help u....

Answer 2

each interior angle is equal.
therefore, each interior angle=360/4=90 degree

each exterior angle is equl.
therefore, each exterior angle=180-0=90 degree