find the measure of each side of a square whose diagonal is 10√2
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0
Answer:
a≈7.07
Step-by-step explanation:
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0
Answer:
10 unit
Step-by-step explanation:
Let the length of side be 'a'.
In square, adjacent sides of equal length intersect each other at 90*. Here, we can use Pythagoras theorem, which says:
⇒ side^2 + side^2 = diagonal^2
⇒ a^2 + a^2 = (10√2)^2
⇒ 2a^2 = 200
⇒ a^2 = 200/2 = 100
⇒ a = √100
⇒ a = 10
Hence, length of each side is 10 unit
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