Find the measure of interior and exterior angles of the following = pentagon
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Answer:
Step-by-step explanation:
No. of sides in a regular Pentagon =5
Sum of exterior angle =360°
each exterior angle =360°/no of sides
=360/5
=72°
THEREFORE each interior angle =180°-72°
=108°
No of sides in a regular pentagon = 5
Sum of exterior angle=360°
each exterior angle=360°/5
=72°
therefore each interior angle =180°-72°
= 108°
also u can find interior angle by formula: [n-2]180° , where n is no . of sides..
as we know a pentagon has 5 sides.
therfore , [ 5 - 2 ] 180° = 3 x 180° = 540°
here 540° is sum of its interior sides..
and there are 5 sides in pentagon ..
so its measure at one side will be 540° / 5 = 108°
hope it helps...
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