Question

Find the measure of sides of a triangle which are in the ratio 3:4:5 and whose

perimeter is 36cm
step by step ​

Answer 1

Sides of the triangle respectively are 9 units , 12 units , 15 units

Step-by-step explanation:

Question :-

Find the measure of sides of a triangle which are in the ratio 3:4:5 and whose perimeter is 36cm

We Have :-

Ratio 3:4:5

Perimeter of the triangle = 36 cm

To Find :-

Sides of the triangle

Formula Used :-

Perimeter of Triangle = Side + Side + Side

Solution :-

Let the sides be -

3x

4x

5x

Perimeter of Triangle = Side + Side + Side

36 = 3x + 4x + 5x

36 = 12 x

x = 36 / 12

x = 3

Sides are :-

3x = 3 × 3 = 9 units

4x = 4 × 3 = 12 units

5x = 5 × 3 = 15 units

Sides of the triangle respectively are 9 units , 12 units , 15 units

Answer 2

Answer:

Given :-

• A side of a triangle which are in the ratio of 3 : 4 : 5 and whose perimeter is 36 cm.

To Find :-

• What are the measure of sides of a triangle.

Solution :-

Let, the first side be 3x

Second side be 4x

And, the third side will be 5x

According to the question,

↦ $\sf 3x + 4x + 5x =\: 36$

↦ $\sf 7x + 5x =\: 36$

↦ $\sf 12x =\: 36$

↦$\sf x =\: \dfrac{\cancel{36}}{\cancel{12}}$

➠ $\sf\bold{\pink{x =\: 3\: cm}}$

Hence, the required sides of a triangle are :

➲ First side of a triangle :

⇒ $\sf 3x\: cm$

⇒ $\sf 3(3)\: cm$

⇒ $\sf 3 \times 3\: cm$

➦ $\sf\bold{\red{9\: cm}}$

➲ Second side of a triangle :

⇒ $\sf 4x\: cm$

⇒ $\sf 4(3)\: cm$

⇒ $\sf 4 \times 3\: cm$

➦ $\sf\bold{\red{12\: cm}}$

And,

➲ $\sf 5x\: cm$

⇒ $\sf 5(3)\: cm$

⇒ $\sf 5 \times 3\: cm$

➦ $\sf\bold{\red{15\: cm}}$

$\therefore$ The measure of sides of a triangle is 9 cm, 12 cm and 15 cm respectively.