find the measure of the angle between the hour hand and minute hand of a clock at 15 minutes past 2 answer
Answers
Answer = 22.5
Step-by-step =
↓
↓2
↓2
↓2
↓2
↓2 <2:15<
↓2 <2:15< ↓
↓2 <2:15< ↓3
↓2 <2:15< ↓3
↓2 <2:15< ↓3 ' O clock
↓2 <2:15< ↓3 ' O clock(60
↓2 <2:15< ↓3 ' O clock(60 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 60
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60 0 +7.5
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60 0 +7.5 0
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60 0 +7.5 0 ))=22.5
↓2 <2:15< ↓3 ' O clock(60 0 ) (90 0 )when minute hand rotates 15 min hour hand rotate 6015 ×30 0 =7.5 0 So, angle at 2:15 is =(90 0 −(60 0 +7.5 0 ))=22.5 0
Therefore the measure of the angle between the hour hand and minute hand of a clock at 2 hours and 15 minutes is 30°.
Given:
The time which shorthand is showing = 2 hour
The time which minute hand showing = 15 minutes
To Find:
The measure of the angle between the hour hand and minute hand of a clock at 2 hours and 15 minutes.
Solution:
The given question can be answered as shown below.
⇒ The total angle of the clock is 360°.
⇒ If we divide this 360° into 4 parts we have 4 quarters as 12 - 3; 3 - 6; 6 - 9; and 9 - 12.
⇒ So each interval is divided into 90°.
⇒ So if we analyze 12-3 quarters, the total angle is 90°.
⇒ If the 12-3 quarter is divided into 3 parts namely, 12-1; 1-2; and 2-3 each of the 3 parts has an angle of 90°/3 = 30°
⇒ In the question, the hour hand is on 2 and the minute hand is on 3 so the angle between them is 30°.
Therefore the measure of the angle between the hour hand and minute hand of a clock at 2 hours and 15 minutes is 30°.
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