Question

find the measure of the angle of a parallelogram whose one angle is 60 more than twice it's adjacent angles​

Answer 1

Answer:

first angle =X

second angle=60+2x

as they are adjacent

60+2x+X=180

60+3x=180

3x=180-60

3x=120

x,=120/3=40

second angle is 60+2x

60+2*40

60+80

140