Question

find the measure of the angle of a triangle in the following case if one angle of a triangle is 80 degree and the other two angles are in the ratio 3 :7​

Answer 1

Answer:

According to the Question:

Side A=80

Side B=3x

Side C=7x

A + B + C = 180

=>80 + 3x + 7x = 180

=>10x + 80=180

=>10x = 180 - 80

=> 10x=100

=> x= 100 / 10

=> x= 10

Therefore,

Side A=80

Side B=3x=3 * 10=30

Side C=7x=7 * 10=70

Answer 2

Let the no. Be X

3x+7x+ 80=180

10x=180-80

Hence,X=10

Second angle =30

Third angle =70