find the measure of the angles of a triangle if one angle of a triangle is 80 degree and the other two angles are in the ratio 3 is to 7
Answers
Answered by
4
80+x=180
x=180-80
x=100 degree
two angles are in the ratio 3 is to 7
3:7
let common multiple be y.
3y+7y=100
10y=100
y=100/10
y=10
3y=10×3=30 degree
7y=7×10=70 degree
the measures of other two angles are 30 and 70 degree.
Answered by
5
Answer:
Let the angles be 3x and 7x
Step-by-step explanation:
Given one angle =80°
Therefore We know that Measure of the angles of a triangle =180°
=3x + 7x+80°=180°
=10x +80°=180°
=10x =180°- 80°
=10x = 100°
= x= 100÷10
=x= 10 °
The angles are 10 × 3 and 10 × 7 =30°and 70° .
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