Question

Find the measure of the angles of a triangle
if one of its angles is 80° and the other two
angles are in the ratio 3:7​

Answer 1

Answer:

80,30,70

Step-by-step explanation:

Let's say Angle A = 80 °

then, Angle B = 3x°

Angle C = 7x°

By angle sum property

Angle A + Angle B + Angle C = 180°

therefore, 80° + 3x° + 7x° = 180°

80 + 10x = 180

10x = 100

X = 100/10

X = 10

The angles of the triangle are

80, 30, 70

Answer 2

Answer :-

The other two angles of the triangle are 30° and 70° respectively.

Explanation :-

Given :

• One of the angle of triangle = 80°
• Ratio of other two angles = 3 : 7

To find :

The measure of other two angles of the triangle.

Solution :

Let the angles be '3x' & '7x'

We know that,

Sum of the angles of triangle = 180°

.°. 3x + 7x + 80° = 180°

or, 3x + 7x = 180° - 80°

or, 3x + 7x = 100°

or, 10x = 100°

or, x = 100°/10

.°. x = 10°

Hence, the value of x is 10°.

Now,

The first angle => (3 × 10)° = 30°

& The second angle => (7 × 10)° = 70°

Hence, the measure of the other two angles is 30° and 70°.