Find the measure of the exterior angles formed by producing the sides of the polygon in order with
(1) 6 sides
(ii) 9 sides
(iii) 15 sides.
Answers
Answer:
Step-by-step explanation:
In A Haxagon Each Of Its Exterior Side Is Produced And Angle Formed Are 4x , 2x+6,3x-1,5x-9, X + 9 And 2x-2
Now We Need To Find Measures OF Each Exterior Angle.
The Exterior Angle That Are Given Are ...
Now We Need To Find Measures of all angle.
So For That Follow This Simple Steps ....
1 ) We know that....
Theorem States That In Any Polygon With Any Side Sum Of Their Exterior
Angle Will Always Add Upto 360°.
So Now According to this statement we have
So Now Open The Bracket And Compare The Like Terms ..
We Have..➡️
That is ➡️
Now Taking 3 To Rhs We Have ➡️
That is ➡️
Now taking 17 to RHS we have ➡️
So Now We know the value of X
2) So Now Put This Value Of X In Each Angle .
Angle 1 = 4x ➡️ 4 × 21 = 84°
Angle 2 = 2x +6 ➡️ 2 × 21 + 6 = 48°
Angle 3 = 3x-1➡️3 × 21 -1 = 62°
Angle 4 = 5x -9➡️5 × 21 -9= 96°
Angle 5 = X + 9➡️ 21 +9 = 30°
Angle 6 = 2x- 2➡️2 × 21 - 2 = 40°
Hence The Required Answer Is .....
84 ° , 48° , 62° , 96° , 30° And 40°
Thought of the day.....
“I slept and I dreamed that life is all joy. I woke and I saw that life is all service. I served and I saw that service is joy.”
– Kahlil Gibran
Be BRAINLY
Hi
I dont now the answer but I think
the answer isn 1 )6sides