Question

find the measure of the missing angles transversal

Answer 1

1st qn

angle 4 = 135° (voa)

angle 2 = 180°-135°(linear)

= 45°

angle 3 = 45°(voa)

2nd qn

angle 2 = 180°-82°(linear)

= 98°

angle 1 = 180°-98°(supplementary)

= 82°

3rd qn

4x°+x°=180°

5x=180

x=180/5

x=36°

4x°=4(36°)

=144°

4th qn

angle 2 = 180°-120°

= 60°

angle 1 =180°-60°

=120°

5th qn

x°-20+x°=180°(linear)

2x°-20°=180°

2x°=180°+20°

2x°=200°

x°=200°/20°

x°=10°

x°-20°=10°-20°

= -10°

Hope it helps you

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Answer 2

Answer:

Step-by-step explanation: