Math, asked by bhavanapandey29, 10 months ago

find the measure of the side of a rhombus if it's diagonal measure 35cm and 28 cm​

Answers

Answered by Anonymous
7

Step-by-step explanation:

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Let ABCD be a rhom. with O as intersection of diagonals.

And we know that diagonal bisect each other

>OA=1/2AD=35/2=17.5

>OB=1/2BC=28/2=14

By Pythagoras Theorem

AB^2=OA^2+OB^2

AB^2=17.5^2+14^2

AB^2=502.25

AB=√502.25

AB=22.14

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