find the measure of the side of a rhombus if its diagonals measure 35 cm and 28 cm
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Let ABCD be a rhom. with O as intersection of diagonals.
And we know that diagonal bisect each other
>OA=1/2AD=35/2=17.5
>OB=1/2BC=28/2=14
By Pythagoras Theorem
AB^2=OA^2+OB^2
AB^2=17.5^2+14^2
AB^2=502.25
AB=√502.25
AB=22.14
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