find the measure of the smaller angle
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D : A = 2: 1
D/A = 2/1
D = 2A ......(1)
A = B ......(2)
C = B - 20. ..(3)
A + B+C+D =360°
B + B + B - 20 + 2× A = 360°. 【 from eq. 1,2 and 3】
3B -20 + 2 B = 360°
5B - 20 =360°
5B = 380°
B = 76°
A = B = 76°
D = 2A
= 2 ×76
= 152°
C = B -20
= 76 - 20
= 56
•• HENCE , Angle C is the smallest
D/A = 2/1
D = 2A ......(1)
A = B ......(2)
C = B - 20. ..(3)
A + B+C+D =360°
B + B + B - 20 + 2× A = 360°. 【 from eq. 1,2 and 3】
3B -20 + 2 B = 360°
5B - 20 =360°
5B = 380°
B = 76°
A = B = 76°
D = 2A
= 2 ×76
= 152°
C = B -20
= 76 - 20
= 56
•• HENCE , Angle C is the smallest
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