Find the measure of the third angle of a triangle whose two angles are 116degrees,30degrees
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Sum of all angles of a Triangle=180°
Given 116°+30°+x°=180°
146°+x°=180°
x°=180°-146°
x°=34°
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Answered by
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Let the third anhle of triangle be x
Sum of all sides of triangle = 180 degree
116+30+x=180
X=180-116-30=34
Sum of all sides of triangle = 180 degree
116+30+x=180
X=180-116-30=34
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