Find the measure of the unknown angle in the following figure
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Answer:
From the figure
a=d are vertically opposite angles
d=f are corresponding angles
f=110
0
are vertically opposite angles
So we get
a=d=f=110
0
We know that
e+110
0
=180
0
are co-interior angles
e=180−110=70
0
b=c are vertically opposite angles
b=e are corresponding angles
e=g are vertically opposite angles
So we get
b=c=e=g=70
0
Therefore a=110
0
,b=70
0
,c=70
0
,d=110
0
,e=110
0
,f=110
0
and g=70
0
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⇒ GIVEN :
- ∆ ABC is an isosceles triangle.
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⇒ ANSWER :
lets find x
- x + x + 90 = (sum of interior triangle)
- x + x + 90 = 180°
- 2x + 90 = 180°
- 2x = 180 - 90
- 2x = 90
- x = 45°
lets find y
- according to the question AB ll DC
- So,
- x° = y°
- y = 45°
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⇒ FINAL ANSWER :
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