Math, asked by sharviljain, 1 month ago

find the measure of x in the given figure

Attachments:

Answers

Answered by Anonymous
1

Answer:

Number of sides of regular hexagon =6

Sum of all interior angles =(n−2)×180

o

=(6−2)×180

o

=4×180

o

=720

o

Sum of all interior angle =x+x−5+x−5+2x−5+2x−5+2x+20

⇒ 720

o

=9x

⇒ x=

9

720

o

⇒ x=80

o

Answered by jiakher84
0

Answer:

(a)

(a)Sum of all interior angles of quadrilateral =360

(a)Sum of all interior angles of quadrilateral =360 0

(a)Sum of all interior angles of quadrilateral =360 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b)

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c)

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=110

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540 0

(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540 0

Similar questions