find the measure of x in the given figure
Answers
Answer:
Number of sides of regular hexagon =6
Sum of all interior angles =(n−2)×180
o
=(6−2)×180
o
=4×180
o
=720
o
Sum of all interior angle =x+x−5+x−5+2x−5+2x−5+2x+20
⇒ 720
o
=9x
⇒ x=
9
720
o
⇒ x=80
o
Answer:
(a)
(a)Sum of all interior angles of quadrilateral =360
(a)Sum of all interior angles of quadrilateral =360 0
(a)Sum of all interior angles of quadrilateral =360 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b)
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c)
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=110
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540 0
(a)Sum of all interior angles of quadrilateral =360 0 ∴50+130+120+x=300x=60 0 (b) 90+a=180a=90Sum of all angles of quad =360x+70+60+90=360x=140 0 (c) 70+a=180 (Linear pair)a=11060+b=180 (Linear pair)b=120Sum of measures of all angles of pentagon =540 0