Question

Find the measures of all angles of a parallelogram if one angle is 240
less than twice the smallest angle.​

Answer 1

Answer:

let the smallest angle be x

APQ another angle=(240-2x)

As we know that two adjacent angle sum is supplementary= x+240-2x=180

-x=-60

x=60

thus smallest angle is x=60

and another angle=(240-2×60)=120

since opposite Angles are equal of. a parallelogram.

so aother two angles are 60 and 120