Question

Find the measures of all the angles of a parallelogram if one angle is 12* less then the twice of the smallest angle

Answer 1

let one angle be x
therefore other angle  = 2x-12
these angles are unequal (as one is smaller ) so they should be adjacent angles
therefore 3x - 12 = 180 [cointerior angles]
x = 64 and other angle = 116
so angles are 64,116,64 and 116

Answer 2

Let the smallest angle be X then the larger angle Y will be 2X-12.
Sum of adjacent angle is 180.
so,X+Y=180
=X+2X-12=180
=3X=192
=X=192/3
=X=64