Question

find the measures of each angle of a parallelogram if larger angle is 30°, less than twice the smaller angle.

Answer 1

let smaller angle = x

larger angle= 2x-30 (given)

opposite angles of paralelogram are equal

therefore angles are x, x, 2x-30, 2x-30

sum of angles of paralelogram = 360

x+x+2x-30+2x-30=360

6x-60=360

6x=420

x=420/6=70

smaller angle = x = 70

larger angle = 2x-30 = 140-30 = 110

THEREFORE ANGLES OF PARALELOGRAM ARE 70 , 70 , 110 , 110

THANK YOU.............

Answer 2

Answer:

Step-by-step explanation:

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