Question

find the measures of each angle of a parallelogram PQRS if <p=(2x+10), <q(3x-20)​

Answer 1

Answer:

angle p + angle q is equal to 180 (supplymentary angles)

(2x+10) + (3x-20) =180

by solving it we get x= 38

angle p is equal to 86

therefore opposite angle will also be equal to 86

angle q is equal to 94

therefore opposite angle will also be equal to 94

Answer 2

Answer:

IF ANGLE ARE ADJACENT

P+Q=180

2X+ 10+3X-20=180

5X=180+10

5X=190

X=190/5

=38

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Step-by-step explanation: