find the measures of the four angles of a quadrilateralif they are in the ratio 3:5:7:9
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Let angle A = 3x
B = 5x
C = 7x
D = 9x
we know that sum of all angles of quadrilateral is 360°
A+B+C+D = 360°
3x+5x+7x+9x = 360°
24x = 360°
x = 360°/24
x = 15°
So, angle A = 15°
B = 3×15 = 45°
C = 5×15 = 75°
D = 7× 15 = 105°
B = 5x
C = 7x
D = 9x
we know that sum of all angles of quadrilateral is 360°
A+B+C+D = 360°
3x+5x+7x+9x = 360°
24x = 360°
x = 360°/24
x = 15°
So, angle A = 15°
B = 3×15 = 45°
C = 5×15 = 75°
D = 7× 15 = 105°
Shivamkumarkk:
very well
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