Find the measures of x,y and z in the figure, where l//BC
A
B
C
l
x
0
y
0
z
0
750 450
Answers
x+y+z=180
x+y+z=180 o
x+y+z=180 o
x+y+z=180 o 75+x+45
x+y+z=180 o 75+x+45 o
x+y+z=180 o 75+x+45 o =180
x+y+z=180 o 75+x+45 o =180x=180−120
x+y+z=180 o 75+x+45 o =180x=180−120x=60
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180 o y=180−105=75
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180 o y=180−105=75 o
x+y+z=180 o 75+x+45 o =180x=180−120x=60 o l∣∣BC so ∠z=45 o 45+60+y=180 o y=180−105=75 o .