Question

Find the median and range of the data. 55, 60, 35, 51, 29, 63, 72, 91, 85, 82​

Answer 1

Answer:

Step-by-step explanation:

MEDIAN=60

RANGE= BIGGEST-SMALLEST= 62

Answer 2

Answer:

According to question we have to find median and range of given data.

1 ) To find : median

First arrange the given numbers in ascending order,

29, 35, 51, 55, 60, 63, 72, 82, 85, 91

Here n = 10, that is number of observation is even.  

where, n is number of observation

∴  median = $\frac{1}{2}$  $[ (\frac{n}{2} )^{th} term + (\frac{n}{2}+ 1 ) ^{th} term]$

                = $\frac{1}{2} [( \frac{10}{2}) ^{th} term + (\frac{10}{2} + 1) ^{th} term]$

                = $\frac{1}{2} [ (5)^{th} term + (6)^{th} term ]$

 here we know that , 5th term = 60 and 6th term = 63

Therefore,  =  $\frac{1}{2} [ 60 + 63 ]$

                  = $\frac{1}{2} (123)$

                  = 61.5

Hence , median is 61.5 .

now,

2 ) To find : range

The range of a set of data is the difference between the highest and lowest values in the set.

First arrange the given numbers in ascending order,

29, 35, 51, 55, 60, 63, 72, 82, 85, 91

highest value = 91 and lowest value = 29

range = highest value - lowest value

          = 91 -29

         = 62

Hence, range of data is 62.