find the median:‐ class 1500‐2000, 2000‐2500, 2500‐3000, 3000‐3500, 3500‐4000, 4000‐4500, 4500‐5000 and frequency 14, 56, 60, 86, 74, 62, 48.
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Answer:
- first arranged them into proper order, class interval, and find cumulative frequency of the data.
Step-by-step explanation:
- 1500-2000=14=14 2000-2500=56=70 2500-3000=60=130 3000-3500=86=216 3500-4000=74=290 4000-4500=62=352 4500-5000=48=400 find N/2=400/2=200 =check which class inteval cumulative frequency is greater than theN/2. here, 3000-3500 is consider as median class. to median following are required, width., lower limit of median class, N/2, cf, and last frequency of median class. so, median= L +N/2-cf/ f *h =3000+200-130/86×500 = 3000+406=3406
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perfect answer for this question is
Step-by-step explanation:
3406.9
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