Question

.
Find the median class for the following data.
Class 20 - 40 40-60 60 - 80 80 - 100
10
20
12
frequency
22​

Answer 1

Answer:

ClassInterval Frequency c.f.

ClassInterval Frequency c.f. 0−20 6 6

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N =

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 2

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2N

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2N

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2N −c.f

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2N −c.f

ClassInterval Frequency c.f. 0−20 6 6 20−40 8 14 40−60 10 24 60−80 12 36 80−100 6 42 100−120 5 47 120−140 3 50 N=50 Here, N=50, then 2N = 250 =25∴ Median class =60−80We have, l=60,c.f=24,f=12 and h=20Median=l+ f2N −c.f ×h

=60+ 12

=60+ 1225−24

=60+ 1225−24

=60+ 1225−24 ×20

=60+ 1225−24 ×20 =60+1.66

=60+ 1225−24 ×20 =60+1.66 =61.66

Answer 2

Answer:

49

Step-by-step explanation:

l + (n/2-cf)/f *h

40+3/5*10

40+30/5 = 46

* = multiply

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